Distance

[Guest]

Two fixed posts are d feet apart. When n posts are set equally spaced, between the two fixed posts, calculate distance (in feet) apart any two consecutive posts will be.

[Guest]

n posts, so n-1 spaces, plus the 2 spaces between the end posts and the fixed posts. gives n+1 spaces.
So distance between consecutive posts is [d / (n+1)] feet.

or
n posts plus 2 fixed end posts, gives (n+2) - 1 spaces = n+1 spaces and distance between as above calc.

[Guest]

Please give an example. Thanks.

[Guest]

I thought I gave 2 examples above.

Numerical example:-
If 2 fixed posts are 11 feet apart and 10 posts put in between spaced evenly in a straight line, that means 12 posts alltogether, that means 11 spaces alltogether, so 1 foot between consecutive posts.

[Guest]

"So distance between consecutive posts is [d / (n+1)] feet."

"If 2 fixed posts are 11 feet apart and 10 posts put in between spaced evenly in a straight line, that means 12 posts alltogether, that means 11 spaces alltogether, so 1 foot between consecutive posts."



11 / 10 + 1 = 1

Is that what you mean ?

[Guest]

Yes, d=11, n =10, so 10 evenly spaced in a line between each fixed post is 11 spaces between the fixed posts, so (n + 1) = (10+1) = 11.

11 / (10 + 1) = 1, that is 11 spaces each 1 foot wide.

You have written 11/ 10 + 1 which works out to be 1.1 + 1 = 2.1 if done left to right on a calculator.
Using brackets means no ambiguity also rules of BODMAS required.

[Guest]

The numerical example was helpful. I understand now. Thanks.