by Guest » Thu Jul 17, 2014 8:27 pm
15 x 5280 / 3600 = 22 feet per second increase in speed
Ratio of the increase in speed to original speed will equal the ratio of the reduction in time per rev. to the original rev. time.
Let S = original speed in feet per second.
Then Revs per second = (S / 6)
Let T = original Time for 1 rev of wheel. = (6 / S) seconds.
(22 / S) = (1/22) / (6 / S)
(22 / S) = ((1/22) x S) / 6
(22 / S) = (S) / (6 x 22)
S^2 = 6
S = 2.449 feet per second .. OR .. 1.67 miles per hour