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Algebra 2

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Postby Guest » Sat Feb 10, 2024 1:22 pm

Compute [tex]\sqrt{x}[/tex](7 x 5 x 3 x 1 + 16)
Compute [tex]\sqrt{x}[/tex](8 x 6 x 4 x 2 + 16)











Thank you!
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Re: Help questions

Postby Guest » Sun Feb 11, 2024 4:53 pm

I assume the question is [tex]\sqrt{7 \times 5 \times 3 \times 1+16}[/tex]

Applying BODMAS, we multiply first:

[tex]=\sqrt{105+16}[/tex]

We add the radicands together to obtain:

[tex]=\sqrt{121}[/tex]

We obtain the square root:

[tex]=11[/tex]
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Re: Help questions

Postby Guest » Sun Feb 11, 2024 5:22 pm

For the second question which is [tex]\sqrt{8 \times 6 \times 4 \times 2 +16}[/tex]

Applying BODMAS, we multiply the first four numbers from the left:

[tex]=\sqrt{384 +16}[/tex]

Then we add the radicands together to have:

[tex]=\sqrt{400}[/tex]

We evaluate the square root to obtain:

[tex]=20[/tex]

Alternatively, we can approach the question in this manner:

[tex]\sqrt{8 \times 6 \times 4 \times 2 +16}[/tex]

We multiply the first and the fourth numbers from the left to obtain a 16:

[tex]=\sqrt{16 \times 6 \times 4 +16}[/tex]

This is simplified further as:

[tex]=\sqrt{16 \times 24 +16}[/tex]

We bring out the common factor:

[tex]=\sqrt{16 (24+1)}[/tex]

We simplify:

[tex]=\sqrt{16 \times 25}[/tex]

We obtain the square root of each radicand:

[tex]=4 \times 5[/tex]

We multiply the result:

[tex]=20[/tex]
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