PRICES

Algebra 2

PRICES

Postby Guest » Thu Sep 14, 2023 11:23 am

In 1927, an item cost $525. In today's dollars, it would cost \$7500.

2023 - 1927 = 96 years.

What is the formula or steps to determine today's cost ?
Guest
 

Re: PRICES

Postby Guest » Thu Sep 14, 2023 1:49 pm

Inflation is $\left(\left(\frac{\text{Today's Cost}}{\text{Historical Cost}}\right)^{\frac{1}{\text{Number of Years}}} - 1\right) \times 100$

Now, you can calculate X:

$X =\left(\left(\frac{\$7500}{\$525}\right)^{\frac{1}{96}} - 1\right) × 100$

$X \approx (14.2857 - 1) × 100$

$X \approx 13.2857%$
Guest
 

Re: PRICES

Postby Guest » Thu Sep 14, 2023 7:06 pm

Ok, Thanks.
Guest
 


Return to Algebra 2



Who is online

Users browsing this forum: No registered users and 1 guest

cron