Dimensions

Algebra 2

Dimensions

Postby Guest » Mon Dec 16, 2013 6:12 pm

A bookcase is to be constructed with four shelves.

Height is 3 feet longer than width.

Only 30 feet of wood is available.

Calculate dimensions of bookcase.

Thanks for your assistance and time.
Guest
 

Re: Dimensions

Postby Guest » Mon Dec 16, 2013 9:42 pm

Two uprights 7 feet tall and four shelves four feet wide.


so dimensions are 7 feet high by 4 feet wide.

Simple..........
Guest
 

Re: Dimensions

Postby Guest » Mon Dec 16, 2013 10:18 pm

Please post your solution.

Thanks again.
Guest
 

Re: Dimensions

Postby Guest » Tue Dec 17, 2013 7:39 am

Are you actually making a bookcase..??
There is not enough information in the question to give a definitive solution.
I assumed it was made by two uprights with 4 shelves in between.
So the actual overall width will be the width of the shelves plus the thickness of the two uprights...
We don't know the thickness of the wood.

Let W = width of shelves
Then height is (W + 3)

and......Let T = thickness of wood......according to my design...

So... 4W + 2(W + 3) = 30
4W + 2W + 6 = 30
6W = 24
W = 4

So...height is (W + 3) = 7

and Actual width will be 4 + 2T

Dimensions are..... (4 + 2T) feet wide by 7 feet high

..................Simple.........................
Guest
 

Re: Dimensions

Postby Guest » Tue Dec 17, 2013 5:34 pm

I was not making a bookcase. Information given was all the problem stated. Thickness of the shelves was not indicated.

Thanks again.
Guest
 


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