"In terms of "Solid rock sand" + voids = 2/3 x 0.441 = 0.294 cu yards solids + 0.147 cu yards voids
In terms of "Solid rock gravel" + voids = 0.55 x 0.882 = 0.485 cu yards solids + 0.397 cu yards voids"
How did you calculate the .0.147 and 0.397 ?
It tells you this in the question.... Sand is 1/3 voids so must be 2/3 actual sand particles what I called "solid rock sand"....the bits that are actual particles of sand. Similarly for the gravel that question tells you it is 45% voids so must be 55% solid gravel rock particles.
For sand..... 2/3 x 0.441 = 0.294 cu yards solid sand particles and 1/3 x 0.441 = 0.147 cu yards voids in the sand.
For gravel..... 0.55 x 0.882 = 0.485 cu yards solid gravel particles and 0.45 x 0.882 = 0.0.397 cu yards voids in the gravel.
And if you add in the cement powder = 0.22 cu yards solid cement powder particles having no voids .........
The Total of all this is... (0.22 + 0.294 + 0.485) = 1 cu yard of solids particles + (0.00 + 0.147 + 0.397) = 0.544 cu yards of voids.
This gives a total volume of the materials measured out for mixing as... (1.00 + 0.544) = 1.544 cu yards of dry mix material made up of solids+voids.
There are some minor roundings errors now in the calculations because taking calcs to 3 decimal places.........

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