First Derivative Calculator(Solver) with Steps
Free derivatives calculator(solver) that gets the detailed solution of the first derivative of a function.
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Differentiate [tex]- 2300 x + \frac{2600 x}{x + 1} + 12000[/tex] term by term:
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The derivative of the constant [tex]12000[/tex] is zero.
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The derivative of a constant times a function is the constant times the derivative of the function.
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Apply the power rule: [tex]x[/tex] goes to [tex]1[/tex]
So, the result is: [tex]-2300[/tex]
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The derivative of a constant times a function is the constant times the derivative of the function.
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Apply the quotient rule, which is:
[tex]\frac{d}{d x}\left(\frac{f{\left (x \right )}}{g{\left (x \right )}}\right) = \frac{1}{g^{2}{\left (x \right )}} \left(- f{\left (x \right )} \frac{d}{d x} g{\left (x \right )} + g{\left (x \right )} \frac{d}{d x} f{\left (x \right )}\right)[/tex]
[tex]f{\left (x \right )} = x[/tex] and [tex]g{\left (x \right )} = x + 1[/tex].
To find [tex]\frac{d}{d x} f{\left (x \right )}[/tex]:
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Apply the power rule: [tex]x[/tex] goes to [tex]1[/tex]
To find [tex]\frac{d}{d x} g{\left (x \right )}[/tex]:
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Differentiate [tex]x + 1[/tex] term by term:
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The derivative of the constant [tex]1[/tex] is zero.
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Apply the power rule: [tex]x[/tex] goes to [tex]1[/tex]
The result is: [tex]1[/tex]
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Now plug in to the quotient rule:
[tex]\frac{1}{\left(x + 1\right)^{2}}[/tex]
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So, the result is: [tex]\frac{2600}{\left(x + 1\right)^{2}}[/tex]
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The result is: [tex]-2300 + \frac{2600}{\left(x + 1\right)^{2}}[/tex]
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The answer is:
[tex]-2300 + \frac{2600}{\left(x + 1\right)^{2}}[/tex]
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* is multiplication
oo is $\infty$
pi is $\pi$
x^2 is x2
sqrt(x) is $\sqrt{x}$
sqrt[3](x) is $\sqrt[3]{x}$
(a+b)/(c+d) is $\frac{a+b}{c+d}$
The Most Important Derivatives - Basic Formulas/Rules
$\frac{d}{dx}a=0$ (a is a constant)
$\frac{d}{dx}x=1$
$\frac{d}{dx}x^n=nx^{n-1}$
$\frac{d}{dx}e^x=e^x$
$\frac{d}{dx}\log x=\frac1x$
$\frac{d}{dx}a^x=a^x\log x$
$(f\ g)' = f'g + fg'$ - Product Rule
$(\frac{f}{g})' = \frac{f'g - fg'}{g^2}$ - Quotient Rule
$\frac{d}{dx}f(g(x)) = f'(g(x))g'(x)$ - Chain Rule
$\frac{d}{dx}\sin(x)=\cos(x)$
$\frac{d}{dx}\cos(x)=-\sin(x)$
$\frac{d}{dx}\tan(x)=\sec^2(x)$
$\frac{d}{dx}\cot(x)=-csc^2(x)$
$\frac{d}{dx}\arcsin(x)=\frac{1}{\sqrt{1-x^2}}$
$\frac{d}{dx}\arccos(x)=-\frac{1}{\sqrt{1-x^2}}$
$\frac{d}{dx}\arctan(x)=\frac{1}{1+x^2}$
$\frac{d}{dx}\text{arccot}(x)=-\frac{1}{1+x^2}$
$\frac{d}{dx}\text{arcsec}(x)=\frac{1}{x\sqrt{x^2-1}}$
$\frac{d}{dx}\text{arccsc}(x)=-\frac{1}{x\sqrt{x^2-1}}$

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