ako nqkoi moje da go re6i :}

[mimi_mimi_mimi]

tg([alpha] + [pi] /6) , ako cos [alpha] =3/5 i [alpha] [in] (3[pi] /2;2[pi] )

[Реклама]

[ObsCure]

tg([tex]\alpha+\frac{ \pi}{6}[/tex]), [tex]\alpha\in(\frac{3\pi}{2};2\pi)[/tex] и cos[tex]\alpha=\frac{3}{5}[/tex]

Това ли е?

[ганка симеонова]

[tex] sin^{2}\alpha +cos^{2}\alpha =1 ; \alpha \in (\frac{3\pi }{ 2} ;2\pi )=>sin\alpha =-\frac{4}{5 } ; tg\alpha=-\frac{4}{3 } ; tg(\alpha + \frac{\pi }{6 })=\frac{tg\alpha +tg\pi /6}{1-tg\alpha tg\pi /6 }=....=\frac{3(\sqrt{3}-4) }{9+4\sqrt{3} } [/tex]