Гость » Чт мар 24, 2016 11:43 am
[tex]ax - 3 \ge 0[/tex]
7x-4 = ax - 3 или 7x - 4 = -(ax - 3)
7x-4 = ax - 3
7x - ax = 4 - 3
[tex]x = \frac{1}{7 - a}, a\ne 7[/tex]
7x - 4 = -(ax - 3)
7x - 4 = -ax + 3
7x + ax = 4 + 3
[tex]x = \frac{7}{7+a}, a\ne -7[/tex]
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[tex]ax - 3 \ge 0[/tex]
[tex]a \frac{1}{7 - a} - 3 \ge 0[/tex]
[tex]a \frac{7}{7 + a} - 3 \ge 0[/tex]