Solve the equation:
[tex]y^2+ 22y + y^{\frac12}=-114[/tex]
Guest wrote:Solve the equation:
[tex]y^2+ 22y + y^{\frac12}=-114[/tex]
Guest wrote:How do you find that 22y = -144?
Guest wrote:You seem to be an expert and know so much about algebra.....can you solve simple algebra problem for [tex]x[/tex]
[tex]x^{2} = -144[/tex]
Guest wrote:Guest wrote:You seem to be an expert and know so much about algebra.....can you solve simple algebra problem for [tex]x[/tex]
[tex]x^{2} = -144[/tex]
Sure.. Like I said, I've been up late and algebra is not my strong card...
[tex]x^2 = -144[/tex]
[tex]\sqrt{x} = \sqrt{-144}[/tex]
Which is of course an error, can't square root a negative number..
Guest wrote:My guess is we should be able to do......
[tex](a+bi)^2 + 22(a+bi) + (a+bi)^{\frac{1}{2}} = -114[/tex]
And solve a and bi to get an exact answer......
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