How to convert volume to an area?

[Guest]

If I have 1 Litre of water and I spill it on the floor, what would its area be?

[Baltuilhe]

Good afternoon!

[tex]1L = 1 cm^3[/tex]

So, to discover the 'area', you have to fix the thickness of the 'spilt milk'

Another idea is: If you have a room with 3m x 3m = 300cm x 300cm, you can calc the area... and discover the thickness, right?
Like this:
[tex]V=abc\\\\
1=300\cdot 300\cdot h\\\\
h=\dfrac{1}{90\,000}\approx 1,1\times 10^{-5}cm=1,1\times 10^{-4}=1,1\times 10^{-1}\mu m[/tex]

I hope I have helped!

[Guest]

One fix : 1 l[tex]\ne[/tex]1 [tex]cm^{3}[/tex]

1 l=1 liter=1 [tex]dm^{3}[/tex]

[Baltuilhe]

Good afternoon!

[tex]1L = 1 cm^3[/tex]

So, to discover the 'area', you have to fix the thickness of the 'spilt milk'

Another idea is: If you have a room with 3m x 3m = 300cm x 300cm, you can calc the area... and discover the thickness, right?
Like this:
[tex]V=abc\\\\
1=300\cdot 300\cdot h\\\\
h=\dfrac{1}{90\,000}\approx 1,1\times 10^{-5}cm=1,1\times 10^{-4}=1,1\times 10^{-1}\mu m[/tex]

I hope I have helped!

You were right, my mistake!

[tex]1L = 1 dm^3[/tex]

So, to discover the 'area', you have to fix the thickness of the 'spilt milk'

Another idea is: If you have a room with 3m x 3m = 30dm x 30dm, you can calc the area... and discover the thickness, right?
Like this:
[tex]V=abc\\\\
1=30\cdot 30\cdot h\\\\
h=\dfrac{1}{900}\approx 1,1\times 10^{-3}dm=1,1\times 10^{-4}m=1,1\times 10^{-1}mm=110\mu m[/tex]

Now it's right!