Slope-intercept form of equation

Slope-intercept form of equation

Postby Guest » Sun Jul 04, 2021 8:03 am

I would appreciate some help with steps please. I am soooo confused. I think it is (c) but not sure. Thank you!!

Write the slope-intercept form of the equation of the line through the following points.
through (2, 1) and (0, -3)
a) y = 2x - 5
b) y = -3x + 1
c) y = 2x - 3
Guest
 

Re: Slope-intercept form of equation

Postby nathi123 » Sun Jul 04, 2021 9:39 am

c) y = 2x - 3 ; A(2,1)[tex]\Rightarrow 1 = 2.2-3 ; B( 0.-3) \Rightarrow - 3 = 2.0 -3[/tex]

nathi123
 
Posts: 37
Joined: Sun Sep 17, 2017 1:56 pm
Reputation: 33

Re: Slope-intercept form of equation

Postby Guest » Mon Jul 05, 2021 4:50 pm

Write the slope-intercept form of the equation of the line through the following points.
through (2, 1) and (0, -3)
a) y = 2x - 5
b) y = -3x + 1
c) y = 2x - 3

It's easy to check!
If (a) when x= 2,, y= 2(2)- 5= 4- 5= -1. No, the line does not contain (2, 1).

If (b) when x= 2, y= -3(2)+ 1= -6+ 1= -5. No, the line does not contain (2, 1).

If (c) when x= 2, y= 2(2)- 3= 4- 3= 1. The line does contain (2, 1).
To be sure, when x= 0, y= 2(0)- 3= -3. Yes, the line contains both points!
Guest
 

Re: Slope-intercept form of equation

Postby Guest » Mon Jul 12, 2021 3:49 am

slope intercept form of equaton is y = mx + c

given two points (2, 1) and (0, -3), equation of line passing through two points is y - y1 = m(x2 - x1),
where m is (y2-y1)/(x2-x1).

m = (-3-1)/(0-2) = 4/2 = 2

So, equation of line is y - 1 = 2(x - 2)

y - 1 = 2x - 4

y = 2x - 3, which is the required equation of line in slope intercept form.

To learn more concepts of straight line visit https://mathemerize.com/equation-of-straight-lines/
Guest
 


Return to Functions, Graphs, Derivatives



Who is online

Users browsing this forum: No registered users and 1 guest