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z = a + ib → f(z) = a + i(a + b)

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Expand view Topic review: z = a + ib → f(z) = a + i(a + b)

Re: z = a + ib → f(z) = a + i(a + b)

Post by Guest » Thu Jul 19, 2018 6:40 am

I would answer no, because z depends on a

z = a + ib → f(z) = a + i(a + b)

Post by Guest » Wed Jul 18, 2018 12:18 pm

This was a question on my exam.
Is the function
f : C → C,
z = a + ib → f(z) = a + i(a + b)
of the form f(z) = z + w where w does not depend on z?

The answer to this question was YES, because w=ai. But a is det real part of the complex number z, so why is it correct to say that w does not depend on z? Any one who can explain it to me?

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