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Practice
Simple Polygon Area
Easy
Normal
Simple Polygon Area
Problem 1
Find (in cm
2
) the area of a square with side
a=5cm
.
Solution:
The area of a square is found by using the formula [tex]S=a.a=5cm.5cm=25cm^2[/tex].
Problem 2
If the side of a square is
a=1cm
, find its area (in [tex]cm^2[/tex]).
Solution:
The area of a square is given by the formula [tex]S=a.a=1cm.1cm=1cm^2[/tex].
Problem 3
If the sides of a rectangle are
a=3cm
and
b=5cm
, determine its area (in [tex]cm^2[/tex]).
Solution:
The area of a rectangle is given by the formula [tex]S=a.b=3cm.5cm=15cm^2[/tex].
Problem 4
If the sides of a rectangle are
a=2cm
and
b=7cm
, determine its area (in [tex]cm^2[/tex].
Solution:
The area of a rectangle is given by the formula [tex]S=a.b=2cm.7cm=14cm^2[/tex].
Problem 5
In a triangle
ABC
,
AB=5cm
and
CH=8cm
, where [tex]CH \bot AB; H \in AB[/tex].
The area of
ABC
is
[tex]cm^2[/tex]).
Solution:
Since [tex]CH \bot AB; H \in AB[/tex] =>
CH
is the altitude to
AB
. The area of a triangle is given by the formula [tex]S=\frac{1}{2}AB.CH=\frac{1}{2}\cdot 5cm \cdot 8cm=5cm \cdot 4cm=20cm^2[/tex]
Problem 6
In a triangle
ABC
, the side
BC=4cm
and the altitude to it is
AH=3cm
. Determine the area of
ABC
(in [tex]cm^2[/tex]).
Solution:
The area of a triangle is determine by the formula [tex]S=\frac{1}{2}.BC.AH=\frac{1}{2}.4cm.3cm=2cm.3cm=6cm^2[/tex]
Problem 7
In a right triangle
ABC
([tex]\angle ACB=90^{\circ}[/tex]), the sides
AC
and
BC
have respective lengths
7cm
and
8cm
. Determine the area of
ABC
in [tex]cm^2[/tex].
Solution:
The area of a right triangle is given by the formula [tex]S=\frac{1}{2}AC.BC[/tex] if
AC
and
BC
are catheti - in our case they are. So the area is [tex]S=\frac{1}{2}.8cm.7cm=4cm.7cm=28cm^2[/tex]
Problem 8
The area of a square is [tex]S=49cm^2[/tex]. Find the length of its side in centimeters.
Solution:
Since [tex]S=a.a=49cm^2[/tex] => [tex]a^2=49cm^2=(7cm)^2[/tex], so [tex]a=7cm[/tex].
Easy
Normal
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