Linear Equation Problems - easy

Solution:
By substracting 2 from both sides, we get n+2-2=6-2, or n=4

Solution:
We divide both sides by 19:

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Let us denote the number with x. We have the equation

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The equation is defined for . We cross multiply and get
, which is a valid value for x and the solution.

Solution:
We divide both sides of the equation with 4:

Solution:
By adding 5 to both sides, we get z=5+6, or z=11.

Solution:
We add t to both sides of the equation, and we get 5-t+t=0+t, or t=5.

Solution:
We multiply both sides of the equation by 3 in order to get , or b=9.

Solution:
We substract 3c from both sides of the equation to get 3c-3c=8c-3c, or 5c=0. The we divide both sides by 5 and the answer is c=0.

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First we multiply both sides by 8 to get free of the denominator. That yields , or 3a=24. Then we divide both sides by 3 to get a=8.

Solution:
By substracting 7 from both sides, we get n+7-7=13-7, or n=6.

Solution:
By adding 9 to both sides, we get x-9+9=15+9, or x=24.

Solution:
By substracting 1 from both sides, we get 3x+1-1=16-1, or 3x=15. We divide both sides by 3 in order to get the value for x: x=5.

Solution:
We multiply both sides by 5: in order to get x=40.

Solution:
We substract on the right side: 28=7y. Then we divide by 7 in order to get the solution, y=4.

Solution:
We multiply both sides by 17: