by prasanna_chandran » Thu Nov 05, 2009 9:27 am
1st term is 7, last term is 100, d- common difference is 3.
So we need only n, to find out the Sn=1/2 (a 1st term + a nth term) * n
=1/2*(7+100)*n
100=(7+31*3) , where a=7, 3=d, and a(nth) term = 100, and 31 is the (n-1)th term.
total terms= 32.
Sn= 1/2(7+100)*32= 16*107=1712.
Prasanna Chandran