matematika



Sum 7+10+13+15+...+97+100 = ?

Arithmetic and Geometric progressions.

Sum 7+10+13+15+...+97+100 = ?

Postby dduclam » Tue Mar 25, 2008 2:37 am

Find the sum:

P= 7+10+13+15+...+97+100


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Postby Math Tutor » Tue Mar 25, 2008 2:53 am

Are you shure that the problem is not
P = 7 + 10 + 13 + 16 + ... + 97 + 100 ?
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edit

Postby dduclam » Tue Mar 25, 2008 3:33 am

teacher wrote:Are you shure that the problem is not
P = 7 + 10 + 13 + 16 + ... + 97 + 100 ?


Yes,thank you,teacher :) P = 7 + 10 + 13 + 16 + ... + 97 + 100
math is my life
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Postby icb » Wed May 14, 2008 8:10 am

This is an arithmetical progression.
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Postby prasanna_chandran » Thu Nov 05, 2009 9:27 am

1st term is 7, last term is 100, d- common difference is 3.

So we need only n, to find out the Sn=1/2 (a 1st term + a nth term) * n

=1/2*(7+100)*n

100=(7+31*3) , where a=7, 3=d, and a(nth) term = 100, and 31 is the (n-1)th term.

total terms= 32.

Sn= 1/2(7+100)*32= 16*107=1712.
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