matematika



Math10 needs your support
Bookmark and Share      

Basic Differential Equations and Solutions

Separation of variables
f1(x)g1(y)dx + f2(x)g2(y)dy = 0

Solution
solution to separation of variables

Linear first order eqaution
dx/dy + P(x)y = Q(x)

Solution
solution to first order linear eqaution

Bernoulli's equation
dy/dx + P(x)y = Q(x)yn

Solution
Solution to Bernoulli's equation
where v = y1-n.
If n = 1, the solution is
solution with n = 1

Exact equation
M(x,y)dx + N(x,y)dy = 0, where ∂M/∂y = ∂N/part&;x.

Solution
solution to exact eqaution
where ∂x indicates that the integration is to be performed with respect to x keeping y constant.

Homogeneous åquation
dy/dx = F(y/x).

Solution
solution to homogeneous eqautionwhere v = y/x.If F(v) = v, the solution is y = cx.

yF(xy)dx + xG(xy)dy = 0

Solution

where v = xy. If G(v) = F(v), the solution is xy = c.

Linear, homogeneous second order eqaution
d2y/dx2 + a(dy/dx) + by = 0 , a,b are real constant.

Solution
Let m1, m2 are roots of m2 + am + b = 0.Then there are three cases

Case 1.     m1,m2 real and distinct:
ñase1

Case 2.     m1,m2 real and equal:
ñase2

Case 3.     m1 = p + qi,m2 = p - qi:
ñase3

Linear, nonhomogeneous second order equation
d2y/dx2 + a(dy/dx) + by = R(x), a, b are real constants.

Solution
There are three cases corresponding to the above ones.

Case 1
case1

Ñase 2
ñase1

Ñase 3
ñase1

Euler or Cauchy equation
x2d2y/dx2 + a(dy/dx) + by = S(x) .

Solution
Putting x = et, the equation becomes
d2y/dt2 + (a - 1)(dy/dt) + by = S(et)
and can then be solved as the above two entries.

Bessel's equation
x2d2y/dx2 + x(dy/dx) + (λ2x2 - n2)y = 0.

Solution
y = c1Jn(λx) + c2Yn(x).

Transformed Bessel's equation
x2d2y/dx2 + (2p + 1)x(dy/dx) + (α2x2r + β2)y = 0.

Solution


where q = √p2 - β2.

Legendre'e equation
(1 - x2)d2y/dx2 - 2xdy/dx + n(n + 1)y = 0.

Solution
y = c1Pn(x) + c2Qn(y).

Send us math lessons, lectures, tests to:

Math Bookstore   Questions and Answers
Copyright © 2005-2012.