Properties of continuous functions

  • Mathematical definition of continuity of functions
  • Properties of continuous functions
  • Continuity of polynomials and rational functions
  • Continuity of composite finctions
  • The intermediate value theorem

Continuity of a function becomes obvious from its graph

Discontinuous: as f(x) is not defined at x = c

Discontinuous: as f(x) has a gap at x = c.

Discontinuous: not defined at x = c.

Function has different functional and limiting values at x =c.
  • f(x) is undefined at c

  • The limx → c f(x) does not exist.

  • Values of f(x) and the values of the limit differ at the point c

      Definition
A function f(x) is said to be continuous at a point c if the following conditions are satisfied
-f(c) is defined
-limx → c f(x) exist
-limx → c f(x) = f(c)
- If f(x) is continuous at all points in an interval (a, b), then f(x) is continuous on (a, b)

- A function continuous on the interval (-∞; +∞) is called a continuous function
      Example

- f(x) is discontinuous at x = 2 because f(2) is undefined
By definition of g g(2) = 3
limx → 2 g(x) = limx → 2 (x2 - 4)/(x - 2) = limx → 2 (x + 2) = 4
g(x) is discontinuous because
limx → 2 g(x) ≠ g(2)
      Example
f(x) = x2 - 2x + 1
limx → c f(x) = limx → c (x2 - 2x + 1)
f(x) = c2 - 2c + 1
f(x) = f(c)
So, f is continuous at x = c
      THEOREM 2.7.2
Polynomials are continuous functions
If P is polynomial and c is any real number then
limx → c p(x) = p(c)
      Example

If c < 0
f(c) = -c
limx → c f(x) = limx → c |x| = -c
-x may be negative to begin with but since ot approaches c which is positive or 0, we use the first part of the definition of f(x) to evaluate the limit
      THEOREM 2.7.3
If the function f and g are continuous at c then
    - f + g is continuous at c;
    - f - g is continuous at c;
    - f.g is continuous at c;
    - f/g is continuous at c if g(c) ≠ 0 and is discontinuous at c if g(c)=0
      Proof
Let f and g be continuous function at the number c
limx → c f(x) = f(c)
limx → c g(x) = g(c)
limx → c [f(x).g(x)] = limx → c f(x).limx → c g(x) = f(c).g(c)
      Example
h(x) = (x2 - 9)/(x2 - 5x + 6) = f(x)/g(x)
h(x) will be continuous at all points c If g(c) ≠ 0
h(x) is continuous every where except at x = 2 and x = 3

(a) F is discontinuous at x = a

(b) F is discontinuous at x = b

(c) F is discontinuous at x = a, b
      DEFINITION
A function f(x) is called continuous from left at the point c if the conditions and the left column below are satisfied and is called continuous from the right at the point c if the conditions in the right column are satisfied.
f(c) is defined   f(c) is defined
limx → c- f(x) exists   limx → c+ f(x) exists
limx → c- f(x) = f(c)   limx → c+ f(x) = f(c)

      DEFINITION
A function f(x) is said to be continuous on a closed interval [a, b] if the following conditions are satisfied:
-f(x) is continuous on [a, b];
-f(x) is continuous from the right at a;
-f(x) is continuous from the left at b.

      Example
Show that f(x) is continuous on [-3, 3]
f(x) = √9 - x2
for c in (-3, 3)
limx → c f(x) = limx → c9 - x2 = √limx → c 9 - x2 = √9 - c2 = f(c)
So f(x) is continuous on (-3, 3)
Also
limx → 3- f(x) = limx → 3-9 - x2 = √limx → 3- 9 - x2 = 0 = f(3) limx → 3+ f(x) = limx → 3+9 - x2 = √limx → 3+ 9 - x2 = 0 = f(3)
So f(x) is continuous on [-3, 3]
      INTERMEDIATE-VALUE THEOREM
If f(x) is continuous on a closed interval [a, b] and c is any number between f(x) and f(b), inclusive, then there is at least one number x in the interval [a, b] such that f(x) = c

      THEOREM 2.7.10
If f(x) is continuous on [a, b], and if f(a) and f(b) have opposite signs, then there is at least one solution of the equation f(x) = 0 in the interval (a, b)

      Example
    x3 - x - 1 = 0
f(1) = -1         f(2) = 5
This equation cannot be solved readily by factoring because the left side has no simple factors.
Edit
Create a new page
Send us math lessons, lectures, tests, to:
Bookmark this page to Delicious Bookmark this to Digg Bookmark this to co.mments Bookmark this to Blogmarks Bookmark this to Feed Me Links Bookmark this  to Furl Bookmark this to linkaGoGo Bookmark this to Reddit Bookmark this page to Smarking Bookmark this to Spurl Bookmark this to Yahoo! Bookmark this to Google

Questions and Answers
Copyright © 2007.